| | |
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| | | |
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| | | //获取玻璃的厚度：重新选笼子需要按照笼子可放玻璃厚度进行选择 因为子查询排序对主sql无影响，所以先执行子查询获取顺序，然后一次去查询 |
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| | | List<Integer> deviceUsedList = bigStorageCageService.queryFreeDeviceByUsed(glassInfo.getThickness()); |
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| | | List<Integer> deviceUseds = bigStorageCageService.queryFreeDeviceByUsed(glassInfo.getThickness()); |
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| | | List<BigStorageCageDetails> engineerCount1 = baseMapper.selectList( |
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| | | new LambdaQueryWrapper<BigStorageCageDetails>() |
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| | | .notIn(BigStorageCageDetails::getState, Const.GLASS_STATE_OUT,Const.GLASS_STATE_DAMAGE,Const.GLASS_STATE_TAKE) |
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| | | .select(BigStorageCageDetails::getEngineerId) |
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| | | .groupBy(BigStorageCageDetails::getEngineerId) |
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| | | .between(BigStorageCageDetails::getDeviceId, 1, 5) |
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| | | ); |
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| | | List<BigStorageCageDetails> engineerCount2 = baseMapper.selectList( |
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| | | new LambdaQueryWrapper<BigStorageCageDetails>() |
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| | | .notIn(BigStorageCageDetails::getState, Const.GLASS_STATE_OUT,Const.GLASS_STATE_DAMAGE,Const.GLASS_STATE_TAKE) |
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| | | .select(BigStorageCageDetails::getEngineerId) |
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| | | .groupBy(BigStorageCageDetails::getEngineerId) |
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| | | .between(BigStorageCageDetails::getDeviceId, 6, 8) |
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| | | ); |
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| | | if (engineerCount1.size() > engineerCount2.size()) { |
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| | | deviceUsedList.removeIf(device -> device < 6); |
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| | | } else { |
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| | | deviceUsedList.removeIf(device -> device > 5); |
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| | | } |
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| | | if (CollectionUtils.isEmpty(deviceUsedList)) { |
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| | | deviceUsedList = deviceUseds; |
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| | | } |
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| | | for (Integer item : deviceUsedList) { |
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| | | bigStorageCage = bigStorageCageService.getOne(new LambdaQueryWrapper<BigStorageCage>() |
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| | | .eq(BigStorageCage::getRemainWidth, slotWidth) |
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